std::ranges::move_backward

cppreference.com

Example

Run on Compiler Explorer

Vec: type == std::vector<std::string>;

print_vec: (rem: std::string_view, vec: Vec) = {
    std::print("{}[{}]: \n", rem, vec.size());
    for vec do (s : std::string) {
        if s.empty() {
            std::cout << std::string("· ");
        }
        else {
            std::cout << "(s)$ ";
        }
    }
    std::cout << '\n';
}

main: () = {
    a: Vec = ("▁", "▂", "▃", "▄", "▅", "▆", "▇", "█");
    b:= Vec(a.size());

    print_vec("Before move:\n" "a", a);
    print_vec("b", b);

    std::ranges::move_backward(a, b.end());

    print_vec("\n" "Move a >> b:\n" "a", a);
    print_vec("b", b);

    std::ranges::move_backward(b.begin(), b.end(), a.end());
    print_vec("\n" "Move b >> a:\n" "a", a);
    print_vec("b", b);

    std::ranges::move_backward(a.begin(), a.begin() + 3, a.end());
    print_vec("\n" "Overlapping move a[0, 3) >> a[5, 8):\n" "a", a);
}

Output

Before move:
a[8]: 
▁ ▂ ▃ ▄ ▅ ▆ ▇ █ 
b[8]: 
· · · · · · · · 

Move a >> b:
a[8]: 
· · · · · · · · 
b[8]: 
▁ ▂ ▃ ▄ ▅ ▆ ▇ █ 

Move b >> a:
a[8]: 
▁ ▂ ▃ ▄ ▅ ▆ ▇ █ 
b[8]: 
· · · · · · · · 

Overlapping move a[0, 3) >> a[5, 8):
a[8]: 
· · · ▄ ▅ ▁ ▂ ▃